Instead of Boolean, you can keep last() as filter.
Then user can pick "ALL" or "Newest only" with 0 and other
or simplify a litle bit with one more calculations with "Filter".
if [index] =0 then "Newest Only" else "OLD version" end
Max Iteration Issue_SM_10.0.twbx 24.8 KB
Thanks for your reply. It works.
The only issue I now have is: I want "newest only" and "all iterations" for the filter.
When I select "old", it just gives me the old iterations.
And create new calc filed for filter.
if [Parameter 1]="ALL" then "Show"
elseif [index] =0 then "Show"
Only filter "Show"
BTW, could you mark my answer as correct to close the thread.
Awesome. Thanks Shin.
You are welcome.